GATE EC 1991 Electromagnetics Solution Q 3

GATE EC 1991 Electromagnetics Solution Q 3

In a board side array of 20 isotropic radiators, equally spaced at distance of \lambda/2, the beam width between first nulls is_____.

(a) 51.3 degrees

(b) 11.46 degrees

(c) 22.9 degrees

(d) 102.6 degrees

Ans :- (b)

Explanation

n = 20 and  d=\frac\lambda2

BWFN = \frac{2\lambda}{nd}rad

BWFN = \frac{2\lambda}{20{\displaystyle\frac\lambda2}} BWFN = \frac{2\lambda}{20{\displaystyle\frac\lambda2}}\frac{180}\pi degree =\frac{36}\pi=11.46^o

Become PRO At Electromagnetics Basics With Our 4 Ultimate Visual FREE E-Books On Coordinate Systems & Transformations

GET THEM NOW!

MORE QUESTIONS

Sign up for our Newsletter

Scroll to Top

NAGPUR UNIVERSITY

PUNE UNIVERSITY

MUMBAI UNIVERSITY