GATE EC 1993 Electromagnetics Solution Q 4

GATE EC 1993 Electromagnetics Solution Q 4

Consider a transmission line of characteristic impedance 50 ohm. Let it be terminated at one end by (+j 50)ohm. The VSWR produced by it in the transmission line will be

(a) + 1

(b) 0

(c) \infty

(d) + j

Ans :- c)

Explanation

\Gamma=\frac{Z_L-Z_0}{Z_L+Z_0} \Gamma=\frac{j50-50}{j50+50}=\frac{-50+j50}{50+j50} \left|\Gamma\right|=\frac{\sqrt{\left(50\right)^2+\left(50\right)^2}}{\sqrt{\left(50\right)^2+\left(50\right)^2}}=1 VSWR = \frac{1+\left|\Gamma\right|}{1-\left|\Gamma\right|}=\frac{1+1}{1-1}=\frac20=\infty

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