GATE EC 2002 Electromagnetics Solution Q 1

GATE EC 2002 Electromagnetics Solution Q 1

The electric field on the surface of a perfect conductor is 2 V/m. The conductor is immersed in water with \in=80\in_0. The surface charge density on the conductor is____. { \varepsilon=\frac{10^{-9}}{36\pi}\frac Fm}

a) 0\;C/m^2

b) 2\;C/m^2

c) 1.8\times10^{-11}C/m^2

d) 1.41\times10^{-9}C/m^2

Ans- d)

Explanation

D=\rho_s=\in\;E=80\times\in_0\times2

Putting values we can get the answer.

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