GATE EC 2014 Electromagnetics Solution Q 10

GATE EC 2014 Electromagnetics Solution Q 10

A region shown below contains a perfect conducting half-space and air. The surface current {\overrightarrow K}_s on the surface of the perfect conductor is {\overrightarrow K}_s=\widehat x2 amperes per meter. The tangential \overrightarrow H field in the air just above the perfect conductor is

GATE EC 2014 Electromagnetics Solution img4 - Grad Plus

a) \left(\widehat x+\widehat z\right)\;amperes\;per\;meter

b) \widehat x2\;amperes\;per\;meter

c) -\widehat z2\;amperese\;per\;meter

d) \widehat z2\;amperes\;per\;meter

Ans-(d)

Explanation

According to magnetic boundary conditions. We have,

{\overrightarrow H}<em>{t2}-{\overrightarrow H}</em>{t1}=\widehat{K_S}\times a_N

In this given question the tangential field \overrightarrow H in the air just above the perfect conductor is asked i.e. {\overrightarrow H}_{t2}

We know the tangential component of H inside the conductor is zero i.e. {\overrightarrow H}_{t1}=0

\begin{array}{l}{\overrightarrow H}<em>{t1}=0\\{\overrightarrow H}</em>{t2}=\left(\widehat x2\right)\;\times\left(\;\widehat y\right)\\{\overrightarrow H}_{t2}=2\;\widehat z\;A/m\end{array}

Become PRO At Electromagnetics Basics With Our 4 Ultimate Visual FREE E-Books On Coordinate Systems & Transformations

GET THEM NOW!

MORE QUESTIONS

Sign up for our Newsletter

Scroll to Top

NAGPUR UNIVERSITY

PUNE UNIVERSITY

MUMBAI UNIVERSITY