**1. Choose the correct option.**

i) A particle performs linear S.H.M. starting from the mean position. Its amplitude is *A *and time period is *T.* At the instance when its speed is half the maximum speed, its displacement x is

(A) √3 ⁄ 2 *A*

(B) 2 ⁄√3 *A*

(C) *A *⁄2

(D)1/√2* A*

ii) A body of mass 1 kg is performing linear S.H.M. Its displacement x (cm) at *t *(second) is given by x = 6 sin (100*t* + π/4). Maximum kinetic energy of the body is

(A) 36 J

(B) 9 J

(C) 27 J

(D) 18 J

iii) The length of second’s pendulum on the surface of earth is nearly 1 m. Its length on the surface of moon should be [Given: acceleration due to gravity *(g) *on moon is 1/6 ^{th} of that on the earth’s surface]

(A) 1/6 m

(B) 6 m

(C) 1/36 m

(D) 1/√6 m

iv) Two identical springs of constant *k *are connected, first in series and then in A metal block of mass *m *is suspended from their combination. The ratio of their frequencies of vertical oscillations will be in a ratio

(A) 1:4

(B) 1:2

(C) 2:1

(D) 4:1

v) The graph shows variation of displacement of a particle performing H.M. with time *t. *Which of the following statements is correct from the graph?

(A) The acceleration is maximum at time

(B) The force is maximum at time 3T/4.

(C) The velocity is zero at time T/2.

(D) The kinetic energy is equal to total energy at time T/4.

**2. Answer in brief.**

i) Define linear simple harmonic motion.

ii) Using differential equation of linear S.H.M, obtain the expression for (a) velocity in S.H.M., (b) acceleration in H.M.

iii) Obtain the expression for the period of a simple pendulum performing S.H.M.

iv) State the laws of simple pendulum.

v) Prove that under certain conditions a magnet vibrating in uniform magnetic field performs angular S.H.M.

3. Obtain the expression for the period of a magnet vibrating in a uniform magnetic field and performing S.H.M.

4. Show that a linear S.H.M. is the projection of a U.C.M. along any of its diameter.

5. Draw graphs of displacement, velocity and acceleration against phase angle, for a particle performing linear S.H.M. from (a) the mean position (b) the positive extreme position. Deduce your conclusions from the graph.

6. Deduce the expressions for the kinetic energy and potential energy of a particle executing S.H.M. Hence obtain the expression for total energy of a particle performing S.H.M and show that the total energy is conserved. State the factors on which total energy depends.

7. Deduce the expression for period of simple pendulum. Hence state the factors on which its period depends.

8. At what distance from the mean position is the speed of a particle performing S.H.M. half its maximum speed. Given path length of S.H.M. = 10 cm.

[Ans: 4.33 cm]

9. In SI units, the differential equation of an S.H.M. is $latex \frac{d^2x}{dt^2}$=-36x . Find its frequency and period.

[Ans: 0.955 Hz, 1.05 s]

10. A needle of a sewing machine moves along a path of amplitude 4 cm with frequency 5 Hz. Find its acceleration($latex \frac1{30}$)^{ }s after it has crossed the mean position.

[Ans: 34.2 m/s^{2}]

11. Potential energy of a particle performing linear S.H.M is 0.1 π^{2} x^{2} If mass of the particle is 20 g, find the frequency of S.H.M.

[Ans: 1.581 Hz]

12. The total energy of a body of mass 2 kg performing S.H.M. is 40 J. Find its speed while crossing the centre of the path.

[Ans: 6.324 cm/s]

13. A simple pendulum performs S.H.M of period 4 seconds. How much time after crossing the mean position, will the displacement of the bob be one third of its amplitude.

[Ans: 0.2163 s]

14. A simple pendulum of length 100 cm performs S.H.M. Find the restoring force acting on its bob of mass 50 g when the displacement from the mean position is 3 cm.

[Ans: 1.48 x 10^{-2} N]

15. Find the change in length of a second’s pendulum, if the acceleration due to gravity at the place changes from 9.75 m/s^{2} to 9.8 m/s^{2}.

[Ans: Decreases by 0.0051 m]

16. At what distance from the mean position is the kinetic energy of a particle performing S.H.M. of amplitude 8 cm, three times its potential energy?

[Ans: 4 cm]

17. A particle performing linear S.H.M. of period 27^{–}c seconds about the mean position 0 is observed to have a speed of *b√3 m / *s , when at a distance *b *(metre) from 0. If the particle is moving away from 0 at that instant, find the time required by the particle, to travel a further distance *b.*

[Ans: π/3 s]

18. The period of oscillation of a body of mass m_{1} suspended from a light spring is *T* .When a body of mass m_{2} is tied to the first body and the system is made to oscillate, the period is *2T*. Compare the masses *m*_{1} and *m _{2 }*[Ans: 1/3]

19. The displacement of an oscillating particle is given by *x= *asin*ωt* + bcos*ωt* where *a, b *and *ω** *are constants. Prove that the particle performs a linear S.H.M. with amplitude *A= *$latex \sqrt{a^2+b^2}$

20. Two parallel S.H.M.s represented by x_{1} = 5sin (4π *t + π*/3) cm and x_{2} = 3sin (4π*t* + π/4) cm are superposed on a Determine the amplitude and epoch of the resultant S.H.M.

[Ans: 7.936 cm, 54° 23′]

21. A 20 cm wide thin circular disc of mass 200 g is suspended to a rigid support from a thin metallic string. By holding the rim of the disc, the string is twisted through 60° and released. It now performs angular oscillations of period 1 second. Calculate the maximum restoring torque generated in the string under undamped (π^{3} ≈ 31)

[Ans: 0.04133 N m]

22. Find the number of oscillations performed per minute by a magnet is vibrating in the plane of a uniform field of 1.6 x 10^{-5} Wb/m^{2}. The magnet has moment of inertia 3 x 10^{-6} kg/m^{2} and magnetic moment 3 A m^{2}.

[Ans :38.19 osc/min.]

23. A wooden block of mass m is kept on a piston that can perform vertical vibrations of adjustable frequency and amplitude. During vibrations, we don’t want the block to leave the contact with the piston. How much maximum frequency is possible if the amplitude of vibrations is restricted to 25 cm? In this case, how much is the energy per unit mass of the block? (g ≈ π^{2} ≈ 10 m s ^{-2} )

[Ans: *n*_{max }= 1/s, E/m = 1.25 J/kg]

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