Q.33. If \frac{dy}{dx}=y+3 and y(0) = 2, then y(log 2) =
A. 5
B. 7
C. 13
D. -2
Answer :- B. 7
Explanation :- \frac{dy}{dx}=y+3
\frac{dy}{y+3}=dxIntegrating on both sides, we get
\int \frac{dy}{y+3}=\int dx+clog (y+3) = x+c –(i)
y=2 when x=0 … (Given )
log (2+3) = 0 + c
c= log 5
log(y+3) = x + log 5 [ from (i) ]
y+3 = 5ex
y= 5ex – 3
y(log 2) = 5 elog 2 – 3 = 10 – 3 = 7