MHT-CET Full Test-9 Mathematics Que-33 Solution

Question-33 If \vec{a}, \vec{b}, \vec{c} are three non – coplanar vector, then \frac{\vec{a} \cdot(\vec{b} \times \vec{c})}{(\vec{c} \times \vec{a}) \cdot \vec{b}}+\frac{\vec{b} \cdot(\vec{a} \times \vec{c})}{\vec{c} \cdot(\vec{a} \times \vec{b})}=

A) 0

B) 2

C) -2

D) None

Answer: A) 0

Explanation

\begin{aligned} & \frac{\vec{a} \cdot(\vec{b} \times \vec{c})}{(\vec{c} \times \vec{a}) \cdot \vec{b}}+\frac{\vec{b} \cdot(\vec{a} \times \vec{c})}{\vec{c} \cdot(\vec{a} \times \vec{b})} \ & =\frac{\left[\begin{array}{lll} \vec{a} & \vec{b} & \vec{c} \end{array}\right]}{\left[\begin{array}{lll} \vec{c} & \vec{a} & \vec{b} \end{array}\right]}+\frac{\left[\begin{array}{lll} \vec{b} & \vec{a} & \vec{c} \end{array}\right]}{\left[\begin{array}{lll} \vec{c} & \vec{a} & \vec{b} \end{array}\right]} \ & =\frac{\left[\begin{array}{lll} \vec{a} & \vec{b} & \vec{c} \end{array}\right]}{\left[\begin{array}{lll} \vec{c} & \vec{a} & \vec{b} \end{array}\right]}-\frac{\left[\begin{array}{lll} \vec{a} & \vec{b} & \vec{c} \end{array}\right]}{\left[\begin{array}{lll} \vec{c} & \vec{a} & \vec{b} \end{array}\right]}=0 \end{aligned}
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