Question-12 Which from following cations will form most stable complex with same ligand?
(A) Cu^{2+}
(B) Co^{2+}
(C) Mn^{2+}
(D) Fe^{2+}
Answer : (A)
Explanation:
The stability order of divalent metal ion complexes is given by Irving-William order. The order is:
Cu^{2+} > Ni^{2+} > Co^{2+} > Fe^{2+} > Mn^{2+} > Cd^{2+}