MHT-CET Physics and Chemistry Full Test-17 PHY-QUE-15 Solutions

Question-15 For an ideal gas, the density of the gas is $\rho_0$ when temperature and pressure of the gas are $T_0$ and $P_0$ respectively. when the temperature of the gas is $2T_0$ , its pressure becomes $3P_0$ . The new density will be

(A) $\frac{2}{3}\rho_0$

(B) $\frac{3}{4}\rho_0$

(D) $\frac{3}{2}\rho_0$

Answer : (D)

Explanation:

Density ∝ $\frac{P}{T}$

So, $\frac{d_2}{d_1}=\frac{P_2}{P_1}\times\frac{T_1}{T_2}$

∴ The new density is:

d_2=\rho_0\times\frac{3P_0}{2T_0}\times\frac{T_0}{P_0}

d_2=\frac{3}{2}\rho_0

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