Question-50 The voltage between the plates of a parallel plate capacitor of capacity 1\ \mu F is changing at the rate of 4\ V/s. the displacement current in the capacitor is
(A) 4\ \mu A
(B) 3\ \mu A
(C) 1\ \mu A
(D) 6\ \mu A
Answer : (A)
Explanation:
Q = CV
Displacement current,
∴ i_c = \frac{dQ}{dt} = C \frac{dV}{dt}
∴ i_c = 1 × 10^{-6} × 4 = 4 μA