MHT-CET Physics and Chemistry Full Test-17 PHY-QUE-6 Solutions

Question-06 In series LCR resonant circuit, R=800\ \Omega, C=2\ \mu F and voltage across resistance is 200\ V. The angular frequency is 250\ rad/s. At resonance, the voltage across the inductance is

(A) 400\ V

(B) 250\ V

(C) 1000\ V

(D) 500\ V

Answer : (D)

Explanation:

At resonance in series LCR circuit,

X_L=X_C

\omega L=\frac{1}{\omega C} ….(i)

I=\frac{V_R}{R}

Now, voltage across inductor is

V_L=I X_L V_L=\frac{V_R}{R}\times X_L V_L=\frac{V_R}{R}\times \omega L

V_L=\frac{V_R}{R}\times \frac{1}{\omega C} ….[From (i)]

V_L=\frac{200}{800}\times \frac{1}{250\times2\times10^{-6}}=500\ V