Q.29. What is bond order of F2 molecule?
A. \frac{1}{2}
B. 1
C. 2
D. 3
Answer :- B. 1
Explanation :-
The electronic configuration of F2
(\sigma 1 s)^2 (\sigma^* 1 \mathrm{s})^2 (\sigma 2 s)^2 (\sigma^* 2 \mathrm{s})^2 (\sigma 2 \mathrm{p}_{\mathrm{z}})^2 (\pi 2 \mathrm{p}_{\mathrm{x}})^2 (\pi 2 \mathrm{p}_{\mathrm{y}})^2 (\pi^* 2 \mathrm{p}_{\mathrm{x}})^2 (\pi^* 2 \mathrm{p}_{\mathrm{y}})^2Bond order of F2 molecule = \frac{N_{b}-N_{a}}{2}=\frac{10-8}{2}=1