MHT-CET Physics and Chemistry Full Test-7 CHE-Que-34 Solution

Q.34. Which among the following is haloalkyne?

A. CH3−CH2−CH=CH−X

B. CH3−C=C−CH2−X

C. CH≡C−CH2−CH2−X

D. CH3−CH2−C≡C−X

Answer :- D. CH3−CH2−C≡C−X

Explanation :-

Haloalkynes are compounds that contain a halogen atom (such as fluoride, chlorine, bromine, or iodine) directly bonded to a carbon atom that is part of a carbon-carbon triple bond. In other words, for a compound to be classified as a haloalkyne, it must have a functional group that consists of both a carbon-carbon triple bond (alkyne part) and a halogen atom attached to one of the carbon atoms involved in the triple bond.

Now, let’s examine the provided options:

Option A: CH3−CH2−CH=CH−X

This is not a haloalkyne because it has a carbon-carbon double bond rather than a triple bond, so it would be classified as a haloalkene.

Option B: CH3−C=C−CH2−X

Although this compound contains a carbon-carbon triple bond, the halogen is not attached to one of the carbons participating in that triple bond. Thus, this compound is not a haloalkyne either.

Option C: CH≡C−CH2−CH2−X

Similar to Option B, this compound has a carbon-carbon triple bond and a halogen, but the halogen is not directly attached to the carbon-carbon triple bond, so this is also not a haloalkyne.

Option D: CH3−CH2−C≡C−X

This compound has a carbon-carbon triple bond and a halogen atom directly bonded to one of the carbon atoms of the triple bond, making it a haloalkyne.

Therefore, the correct answer is:

Option D: CH3−CH2−C≡C−X

It is the haloalkyne among the given options because it has the halogen atom (X) directly connected to a carbon that is part of an alkyne group.

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