Q.9. What is the solubility of AgCl(s) if its solubility product is 1.6×10−10 ?
A. 1.26×10−5M
B. 1.00×10−9M
C. 2.6×10−5M
D. 1.56×10−9M
Answer :- A. 1.26×10−5M
Explanation :-
\mathrm{AgCl}_{(\mathrm{s})} \rightleftharpoons \mathrm{Ag}_{(\mathrm{sq})}^{+} + \mathrm{Cl}_{(\mathrm{sq})}^{-} x = 1, \, \mathrm{y} = 1 \mathrm{K}_{\mathrm{sp}} = x^x \mathrm{y}^{\mathrm{y}} \mathrm{S}^{x+\mathrm{y}} = (1)^1 (1)^1 \mathrm{S}^{1+1} = \mathrm{S}^2 \mathrm{S} = \sqrt{\mathrm{K}_{\mathrm{sp}}} = \sqrt{1.6 \times 10^{-10}} = 1.26 \times 10^{-5} \, \mathrm{M}