Sankalp JEE Full Test-4 Question-29 Solution

Question 29. A convex mirror of radius of curvature 30 cm forms an image that is half the size of the object.
The object distance is :

(1) -15 cm

(2) 45 cm

(3) -45 cm

(4) 15 cm

Answer: (1)

Explanation:

The radius of curvature of the convex mirror is R=30 cm

The focal length is f=\frac{R}{2} f=+15 cm

The image is half the size of the object. So the magnification is m=\frac{1}{2}

For a convex mirror, the image of a real object is virtual and erect.

Hence the magnification is positive.

For a mirror, magnification is given by m=\frac{f}{f-u}

Substitute the values, \frac{1}{2}=\frac{15}{15-u}

Solving, 15-u=30 u=-15 cm

Therefore, the object distance is -15 cm.

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