Sankalp JEE Full Test-4 Question-39 Solution

Question 39. The deflection in a moving coil galvanometer falls from 25 divisions to 5 divisions when a shunt of 24 Ω is applied. The resistance of the galvanometer coil is :

(1) 12 Ω

(2) 96 Ω

(3) 48 Ω

(4) 100 Ω

Answer: (2)

Explanation:

Let the current corresponding to one division be x.

Initial deflection is 25 divisions.

So the initial current through the galvanometer is 25x.

After applying the shunt, the deflection becomes 5 divisions.

So the current through the galvanometer is 5x.

The remaining current flows through the shunt.

Current through the shunt is 25x-5x=20x.

Let the resistance of the galvanometer coil be G.

For parallel combination, the potential drop across galvanometer and shunt is equal,

5x\times G=20x\times24.

Cancel x from both sides, 5G=480.

G=96 Ω.

Therefore, the resistance of the galvanometer coil is 96 Ω.

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