Question: 66. Which plot of \ln k vs \frac{1}{T} is consistent with Arrhenius equation?
Answer: Option (4)
Explanation:
The Arrhenius equation is given by k = A e^{-E_a/RT}.
Taking natural logarithm on both sides,
we get \ln k = \ln A - \frac{E_a}{R}\left(\frac{1}{T}\right).
This equation is of the form y = c + mx, where \ln k
is plotted on the y-axis and \frac{1}{T} is plotted on the x-axis.
The slope of the straight line is -\frac{E_a}{R},
which is negative because activation energy E_a is always positive.
Therefore, the correct plot of \ln k versus \frac{1}{T}
must be a straight line with a negative slope.
Among the given plots, option (4) shows a straight line with negative slope,
which is consistent with the Arrhenius equation.