Question: 67. Match List I with List II. Choose the correct answer from the options given below :
(1) A-IV, B-I, C-III, D-II
(2) A-III, B-I, C-II, D-IV
(3) A-IV, B-I, C-II, D-III
(4) A-I, B-IV, C-II, D-III
Answer: Option (3)
Explanation:
In reaction (A), the given compound undergoes ozonolysis, where cleavage of the double bond produces two ketone molecules.
This reaction corresponds to ozonolysis followed by reductive workup using \mathrm{O_3}
and \mathrm{Zn/H_2O}, which is reagent (IV).
In reaction (B), benzene is converted into benzophenone.
This transformation occurs via Friedel–Crafts acylation using benzoyl chloride in the presence of anhydrous \mathrm{AlCl_3}.
Hence, reaction (B) matches with reagent (I).
In reaction (C), cyclohexanol is oxidized to cyclohexanone.
This is an oxidation of a secondary alcohol to a ketone,
which is commonly carried out using \mathrm{CrO_3}.
Therefore, reaction (C) corresponds to reagent (II).
In reaction (D), ethylbenzene is oxidized to potassium benzoate.
Strong oxidation of an alkyl side chain on an aromatic ring to a carboxylate salt is achieved using hot alkaline potassium permanganate,
i.e., \mathrm{KMnO_4/KOH,\ \Delta}.
Thus, reaction (D) matches with reagent (III).
Hence, the correct matching is A-IV, B-I, C-II, D-III,
which corresponds to option (3).