Sankalp NEET Full Test-1 Question-81 Solution

Question: 81. Given below are certain cations. Using inorganic qualitative analysis, arrange them in increasing group number from 0 to VI.

A. \mathrm{Al}^{3+}

B. \mathrm{Cu}^{2+}

C. \mathrm{Ba}^{2+}

D. \mathrm{Co}^{2+}

E. \mathrm{Mg}^{2+}

Choose the correct answer from the options given below:

(1) B, A, D, C, E

(2) \mathrm{B}, \mathrm{C}, \mathrm{A}, \mathrm{D}, \mathrm{E}

(3) \mathrm{E}, \mathrm{C}, \mathrm{D}, \mathrm{B}, \mathrm{A}

(4) \mathrm{E}, \mathrm{A}, \mathrm{B}, \mathrm{C}, \mathrm{D}

Answer: Option (1)

Explanation:

In inorganic qualitative analysis, cations are classified into groups based on the group reagent that precipitates them.

\mathrm{Cu}^{2+} belongs to Group II, as it forms insoluble sulfides with

\mathrm{H}_{2}\mathrm{S} in acidic medium.

\mathrm{Al}^{3+} belongs to Group III, as it precipitates as hydroxide with

\mathrm{NH}_{4}\mathrm{OH} in the presence of \mathrm{NH}_{4}\mathrm{Cl}.

\mathrm{Co}^{2+} belongs to Group IV, as it forms sulfide precipitates with

\mathrm{H}_{2}\mathrm{S} in alkaline medium.

\mathrm{Ba}^{2+} belongs to Group V, as it forms insoluble carbonates with

\mathrm{(NH}_{4})_{2}\mathrm{CO}_{3}.

\mathrm{Mg}^{2+} belongs to Group VI,

as it does not precipitate with common group reagents and is tested separately.

Therefore, the increasing order of group number from 0 to VI is

B, A, D, C, E.

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