Sankalp NEET Full Test-1 Question-84 Solution

Question: 84. The plot of osmotic pressure ( \Pi ) vs concentration (mol \mathrm{L}^{-1} ) for a solution gives a straight line with slope 25.73 \mathrm{~L}^{-1} bar \mathrm{mol}^{-1}. The temperature at which the osmotic pressure measurement is done is:

(Use \mathrm{R}=0.083 \mathrm{~L} bar \mathrm{mol}^{-1} \mathrm{~K}^{-1} )

(1) 37^{\circ} \mathrm{C}

(2) 310^{\circ} \mathrm{C}

(3) 25.73^{\circ} \mathrm{C}

(4) 12.05^{\circ} \mathrm{C}

Answer: Option (1)

Explanation:

Osmotic pressure is related to concentration by the equation

\Pi = C R T

When \Pi is plotted against concentration C,

the slope of the straight line is equal to R T.

Given slope = 25.73 \ \mathrm{L} \ \mathrm{bar} \ \mathrm{mol}^{-1}

Therefore,

R T = 25.73 T = \dfrac{25.73}{0.083} T = 310 \ \mathrm{K}

Converting temperature into degree Celsius,

T = 310 - 273 = 37^{\circ}\mathrm{C}

Hence, the temperature at which the osmotic pressure measurement is done is

37^{\circ}\mathrm{C}.

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