Sankalp NEET Full Test-2 Question-21 Solution

Question 21: A bullet is fired from a gun at the speed of 280 \mathrm{~m} \mathrm{~s}^{-1} in the direction 30^{\circ} above the horizontal. The maximum height attained by the bullet is \left(\mathrm{g}=9.8 \mathrm{~m} \mathrm{~s}^{-2}, \sin 30^{\circ}=0.5\right) :

(1) 1000 m

(2) 3000 m

(3) 2800 m

(4) 2000 m

Answer: Option (1)

Explanation:

The vertical component of the initial velocity is given by

u_y = u \sin\theta

Substituting the given values,

u_y = 280 \times 0.5 = 140 \, \mathrm{m\,s^{-1}}

The maximum height attained by a projectile is given by

H = \frac{u_y^{2}}{2g}

Substituting the values,

H = \frac{(140)^2}{2 \times 9.8} H = \frac{19600}{19.6} H = 1000 \, \mathrm{m}

Hence, the maximum height attained by the bullet is 1000 \, \mathrm{m}.

Therefore, the correct answer is Option (1).