Sankalp NEET Full Test-2 Question-44 Solution

Question 44: A bullet from a gun is fired on a rectangular wooden block with velocity u. When bullet travels 24 cm through the block along its length horizontally, velocity of bullet becomes \frac{u}{3}. Then it further penetrates into the block in the same direction before coming to rest exactly at the other end of the block. The total length of the block is :

(1) 28 cm

(2) 30 cm

(3) 27 cm

(4) 24 cm

Answer: Option (3)

Explanation:

The bullet moves through the wooden block under uniform retardation due to resistive force.

Using the equation of motion v^{2}=u^{2}+2as.

After travelling s_{1}=24 \mathrm{~cm}, the velocity becomes v=\frac{u}{3}.

Substituting in the equation,

\left(\frac{u}{3}\right)^{2}=u^{2}+2a(24).

This gives,

\frac{u^{2}}{9}-u^{2}=48a.

-\frac{8u^{2}}{9}=48a.

a=-\frac{u^{2}}{54}.

Now, the bullet finally comes to rest at the other end of the block,

so final velocity v=0. Let the total length of the block be S.

Again using v^{2}=u^{2}+2aS,

0=u^{2}+2\left(-\frac{u^{2}}{54}\right)S.

u^{2}=\frac{2u^{2}S}{54}.

1=\frac{S}{27}.

S=27 \mathrm{~cm}.

Hence, the total length of the block is 27 cm.

Therefore, the correct answer is Option (3).

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