Sankalp NEET Full Test-2 Question-58 Solution

Question 58: Complete the following reaction :

[A] on treatment with \mathrm{HCN} gives [B]. On heating [B]

with concentrated \mathrm{H_2SO_4}, [C] is formed.

Answer: Option (2)

Explanation:

Compound [A] is cyclohexanone, which reacts with \mathrm{HCN}

to form a cyanohydrin [B].

In this reaction, the \mathrm{CN^-} ion attacks the carbonyl carbon,

and the oxygen is protonated to give a hydroxyl group.

Thus, compound [B] is a cyanohydrin containing both

\mathrm{-OH} and \mathrm{-CN} groups on the same carbon.

On heating [B] with concentrated \mathrm{H_2SO_4},

the nitrile group undergoes hydrolysis to form a carboxylic acid group.

Therefore, the final product [C] is cyclohexene carboxylic acid.

This corresponds to Option (2).

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