Sankalp NEET Full Test-2 Question-61 Solution

Question 61: Identify the product in the following reaction:

A benzene diazonium chloride is treated successively with (i) \mathrm{Cu_2Br_2/HBr}, (ii) \mathrm{Mg/dry\ ether} and (iii) \mathrm{H_2O}.

Answer: Option (4)

Explanation:

In the first step, benzene diazonium chloride reacts with \mathrm{Cu_2Br_2/HBr} to form bromobenzene by the Sandmeyer reaction.

In the second step, bromobenzene reacts with magnesium in dry ether to form phenyl magnesium bromide, which is a Grignard reagent.

In the final step, phenyl magnesium bromide undergoes hydrolysis with

\mathrm{H_2O} to give benzene.

Therefore, the final product of the reaction sequence is benzene.

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