Question 67: Match List – I with List – II :
| List – I | List – II |
|---|---|
| A. Coke | I. Carbon atoms are \mathrm{sp}^{3} hybridised. |
| B. Diamond | II. Used as a dry lubricant |
| C. Fullerene | III. Used as a reducing agent |
| D. Graphite | IV. Cage like molecules |
Choose the correct answer from the options given below :
(1) A-III, B-I, C-IV, D-II
(2) A-III, B-IV, C-I, D-II
(3) A-II, B-IV, C-I, D-III
(4) A-IV, B-I, C-II, D-III
Answer: Option (1)
Explanation:
Coke is an amorphous form of carbon and is commonly used as a reducing agent in metallurgical processes, so A matches with III.
In diamond, each carbon atom is bonded to four other carbon atoms through single bonds,
showing \mathrm{sp^3} hybridisation, so B matches with I.
Fullerenes consist of cage-like structures such as \mathrm{C_{60}}, hence C matches with IV.
Graphite has a layered structure with weak forces between layers,
which allows layers to slide over each other, making it useful as a dry lubricant,
so D matches with II.
Therefore, the correct matching corresponds to option (1).