Question 82: Match List – I with List – II :
| List – I (Oxoacids of Sulphur) | List – II (Bonds) |
|---|---|
| A. Peroxodisulphuric acid | I. Two \mathrm{S}-\mathrm{OH}, Four \mathrm{S}=\mathrm{O}, One S-O-S |
| B. Sulphuric acid | II. Two S-OH, One S=O |
| C. Pyrosulphuric acid | III. Two \mathrm{S}-\mathrm{OH}, Four \mathrm{S}=\mathrm{O}, One S-O-O-S |
| D. Sulphurous acid | IV. Two \mathrm{S}-\mathrm{OH}, Two \mathrm{S}=\mathrm{O} |
Choose the correct answer from the options given below :
(1) A-I, B-III, C-IV, D-II
(2) A-III, B-IV, C-II, D-I
(3) A-I, B-III, C-II, D-IV
(4) A-III, B-IV, C-I, D-II
Answer: Option (4)
Explanation:
Peroxodisulphuric acid contains a peroxide linkage, so it has two \mathrm{S}-\mathrm{OH},
four \mathrm{S}=\mathrm{O} bonds, and one S-O-O-S linkage.
Hence, A matches with III.
Sulphuric acid has two hydroxyl groups and two double bonded oxygen atoms,
so it contains two \mathrm{S}-\mathrm{OH} and
two \mathrm{S}=\mathrm{O} bonds. Hence, B matches with IV.
Pyrosulphuric acid has two sulphur atoms joined by an oxygen atom,
so it contains two \mathrm{S}-\mathrm{OH}, four \mathrm{S}=\mathrm{O},
and one S-O-S bond. Hence, C matches with I.
Sulphurous acid has two hydroxyl groups and one double bonded oxygen atom, so it contains two S-OH and one S=O bond. Hence, D matches with II.
Therefore, the correct matching is A-III, B-IV, C-I, D-II, and the correct option is (4).