Question: 12. A 2 amp current is flowing through two different small circular copper coils having radii ratio 1:2. The ratio of their respective magnetic moments will be
(1) 1: 4
(2) 1: 2
(3) 2: 1
(4) 4: 1
Answer: Option (1)
Explanation:
For a current loop the magnetic moment is proportional to the current and the area of the loop. The magnetic moment is given by \mu=NI A. For single-turn small circular coils we take N=1, so \mu=I A. The area of a circular coil is A=\pi r^2. Since the same current flows through both coils, the ratio of their magnetic moments equals the ratio of their areas:
\displaystyle \frac{\mu_1}{\mu_2}=\frac{I\pi r_1^2}{I\pi r_2^2}=\left(\frac{r_1}{r_2}\right)^2Given the radii ratio r_1:r_2=1:2,
\displaystyle \frac{\mu_1}{\mu_2}=\left(\frac{1}{2}\right)^2=\frac{1}{4}Thus the ratio of their magnetic moments is 1:4,
so Option (1) is correct.