Sankalp NEET Full Test-3 Question-72 Solution

Question: 72. Match the List-I with List-II.

List-I (Mixture)List-II(Method of Separation)
A. \mathrm{CHCl}_{3}+ \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{2} I. Distillation under reduced pressure
B. Crude oil in petroleum industryII. Steam distillation
C. Glycerol from spent-lye III. Fractional distillation
D. Aniline-water IV. Simple distillation

    Choose the correct answer from the options given below.

(1) A-IV, B-III, C-I, D-II

(2) A-IV, B-III, C-II, D-I

(3) A-III, B-IV, C-I, D-II

(4) A-III, B-IV, C-II, D-I

Answer: Option (1)

Explanation:

\mathrm{CHCl}_{3} and aniline have sufficiently different boiling points and do not decompose on heating,

so they can be separated by simple distillation.

Hence, A is matched with IV.

Crude oil consists of a mixture of hydrocarbons with close boiling points.

Such mixtures are separated based on boiling ranges using fractional distillation in the petroleum industry. Hence, B is matched with III.

Glycerol has a very high boiling point and decomposes at atmospheric pressure.

Therefore, it is separated from spent-lye by distillation under reduced pressure.

Hence, C is matched with I.

Aniline and water are immiscible liquids where aniline is steam volatile.

Such mixtures are separated by steam distillation. Hence, D is matched with II.

Thus, the correct matching is A-IV, B-III, C-I, D-II,

corresponding to Option (1).

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