Sankalp NEET Full Test-3 Question-86 Solution

Question: 86. Total number of possible isomers (both structural as well as stereoisomers) of cyclic ethers of molecular formula \mathrm{C}_{4} \mathrm{H}_{8} \mathrm{O} is:

(1) 6

(2) 8

(3) 10

(4) 11

Answer: Option (3)

Explanation:

The molecular formula \mathrm{C}_{4}\mathrm{H}_{8}\mathrm{O} has one degree of unsaturation, which corresponds to one ring.

Since only cyclic ethers are to be considered, the oxygen atom must be present in the ring.

First, consider three-membered cyclic ethers (epoxides).

Substituted oxiranes with four carbon atoms give structural isomers,

some of which show geometrical or optical isomerism, contributing a total of 4 isomers.

Next, consider four-membered cyclic ethers (oxetanes).

Substitution on the oxetane ring gives 3 distinct structural isomers.

Then, consider five-membered cyclic ethers (tetrahydrofurans).

Methyl-substituted tetrahydrofurans give 3 isomers due to different positions of substitution.

Thus, the total number of possible isomers is:

4 + 3 + 3 = 10

Therefore, the total number of structural and stereoisomers of cyclic ethers with molecular formula \mathrm{C}_{4}\mathrm{H}_{8}\mathrm{O} is 10.

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