Sankalp NEET Full Test-4 Question-11 Solution

Question: 11: Match List-I with List-II

List-I (Electromagnetic waves)     List-II (Wavelength)
(a) AM radio waves  (i) 10^{-10} \mathrm{~m}
(b) Microwaves(ii) 10^{2} \mathrm{~m}
(c) Infrared radiations(iii) 10^{-2} \mathrm{~m}
(d) X-rays(iv) 10^{-4} \mathrm{~m}

Choose the correct answer from the options given below

(1) (a) – (iii), (b) – (iv), (c) – (ii), (d) – (i)

(2) (a) – (ii), (b) – (iii), (c) – (iv), (d) – (i)

(3) (a) – (iv), (b) – (iii), (c) – (ii), (d) – (i)

(4) (a) – (iii), (b) – (ii), (c) – (i), (d) – (iv)

Answer: Option (2)

Explanation:

Electromagnetic waves are arranged in the electromagnetic spectrum according to

increasing frequency and decreasing wavelength.

AM radio waves have very large wavelengths, typically of the order of hundreds of metres.

Hence, AM radio waves correspond to wavelength 10^{2} \mathrm{~m}.

Microwaves have wavelengths ranging from about

10^{-3} \mathrm{~m} to 10^{-1} \mathrm{~m}.

The closest given value is 10^{-2} \mathrm{~m}.

Infrared radiations have wavelengths longer than visible light and typically lie around

10^{-4} \mathrm{~m}.

X-rays have very short wavelengths, of the order of 10^{-10} \mathrm{~m}.

Thus, the correct matching is:

(a) AM radio waves – (ii) 10^{2} \mathrm{~m}

(b) Microwaves – (iii) 10^{-2} \mathrm{~m}

(c) Infrared radiations – (iv) 10^{-4} \mathrm{~m}

(d) X-rays – (i) 10^{-10} \mathrm{~m}

Hence, option (2) is correct.

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