Sankalp NEET Full Test-4 Question-24 Solution

Question: 24: A square loop of side 1 m and resistance 1 \Omega is placed in a magnetic field of 0.5 T . If the plane of loop is perpendicular to the direction of magnetic field, the magnetic flux through the loop is

(1) 1 weber

(2) Zero weber

(3) 2 weber

(4) 0.5 weber

Answer: Option (4)

Explanation:

Magnetic flux through a surface placed in a magnetic field is given by

\Phi = B A \cos\theta

where B is the magnetic field, A is the area of the loop, and

\theta is the angle between the magnetic field and the normal to the plane of the loop.

The side of the square loop is 1 m, so its area is

A = 1 \times 1 = 1 \ \text{m}^2

The plane of the loop is perpendicular to the direction of the magnetic field,

which means the magnetic field is parallel to the normal of the loop.

Hence, \theta = 0^{\circ} and \cos 0^{\circ} = 1.

Substituting the values,

\Phi = 0.5 \times 1 \times 1 \Phi = 0.5 \ \text{weber}

Therefore, the magnetic flux through the loop is 0.5 weber.