Question: 34: The peak voltage of the ac source is equal to
(1) \sqrt{2} times the rms value of the ac source
(2) 1 / \sqrt{2} times the rms value of the ac source
(3) The value of voltage supplied to the circuit
(4) The rms value of the ac source
Answer: Option (1)
Explanation:
In an alternating current source, the instantaneous voltage varies sinusoidally with time.
The maximum value of this voltage is called the peak voltage.
The root mean square (rms) value of an alternating voltage is defined as the equivalent direct current voltage that produces the same heating effect in a resistor.
For a sinusoidal alternating voltage, the relation between peak voltage V_0
and rms voltage V_{\text{rms}} is given by
V_{\text{rms}} = \frac{V_0}{\sqrt{2}}.
Rearranging the above expression, the peak voltage is
V_0 = \sqrt{2} \, V_{\text{rms}}.
Thus, the peak voltage of the ac source is \sqrt{2} times the rms value,
making Option (1) correct.