Sankalp NEET Full Test-4 Question-41 Solution

Question: 41: A nucleus of mass number 189 splits into two nuclei having mass number 125 and 64 . The ratio of radius of two daughter nuclei respectively is

(1) 5: 4

(2) 25: 16

(3) 1: 1

(4) 4: 5

Answer: Option (1)

Explanation:

The radius of a nucleus is related to its mass number by the relation R = R_0 A^{1/3},

where R_0 is a constant and A is the mass number.

Let the radii of the two daughter nuclei be R_1 and R_2,

corresponding to mass numbers A_1 = 125 and A_2 = 64 respectively.

The ratio of their radii is given by

\frac{R_1}{R_2} = \left(\frac{A_1}{A_2}\right)^{1/3}.

Substituting the given values,

\frac{R_1}{R_2} = \left(\frac{125}{64}\right)^{1/3}.

Since 125 = 5^3 and 64 = 4^3,

we get \frac{R_1}{R_2} = \frac{5}{4}.

Therefore, the ratio of the radii of the two daughter nuclei is 5 : 4.

Hence, the correct answer is Option (1).

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