Sankalp NEET Full Test-4 Question-70 Solution

Question: 70: Match List-I with List-II.

List – I
(Products formed)
List – II
(Reaction of carbonyl compound with)
(a) Cyanohydrin(i) \mathrm{NH}_{2}\mathrm{OH}
(b) Acetal(ii) \mathrm{RNH}_{2}
(c) Schiff’s base(iii) alcohol
(d) Oxime(iv) HCN

Choose the correct answer from the options given below

(1) (a) – (i), (b) – (iii), (c) – (ii), (d) – (iv)

(2) (a) – (iv), (b) – (iii), (c) – (ii), (d) – (i)

(3) (a) – (iii), (b) – (iv), (c) – (ii), (d) – (i)

(4) (a) – (ii), (b) – (iii), (c) – (iv), (d) – (i)

Answer: Option (2)

Explanation:

Cyanohydrins are formed when a carbonyl compound reacts with hydrogen cyanide HCN,

producing a \mathrm{C(OH)(CN)} group.

Acetals are formed by the reaction of aldehydes or ketones with alcohols in the presence of acid.

Schiff’s bases are formed when a carbonyl compound reacts with a primary amine

\mathrm{RNH}_{2}, resulting in an imine.

Oximes are formed when a carbonyl compound reacts with hydroxylamine

\mathrm{NH}_{2}\mathrm{OH}.

Thus, the correct matching is (a) – (iv), (b) – (iii), (c) – (ii), (d) – (i).

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