Sankalp NEET Full Test-4 Question-88 Solution

Question: 88: For a first order reaction \mathrm{A} \rightarrow Products, initial concentration of A is 0.1 M , which becomes 0.001 M after 5 minutes. Rate constant for the reaction in \min ^{-1} is

(1) 0.4606

(2) 0.2303

(3) 1.3818

(4) 0.9212

Answer: Option (4)

Explanation:

For a first order reaction, the rate constant is given by the integrated rate law

k=\frac{2.303}{t}\log\frac{[A]_0}{[A]_t}

Here, the initial concentration is [A]_0=0.1\ \mathrm{M}, the concentration after time t is [A]_t=0.001\ \mathrm{M}, and the time is t=5\ \mathrm{min}.

Substituting the values,

k=\frac{2.303}{5}\log\frac{0.1}{0.001} k=\frac{2.303}{5}\log 100 k=\frac{2.303}{5}\times 2 k=0.9212\ \min^{-1}

Therefore, the rate constant for the reaction is 0.9212\ \min^{-1}.

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