Question: 130: Match List-I with List-II :
| List-I | List-II |
|---|---|
| (a) Bacteriophage \phi \times 174 | (i) 48502 base pairs |
| (b) Bacteriophage lambda | (ii) 5386 nucleotides |
| (c) Escherichia coli | (iii) 3.3 \times 10^{9} base pairs |
| (d) Haploid content of human DNA | (iv) 4.6 \times 10^{6} base pairs |
Choose the correct answer from the options given below:
(1) (a) – (i), (b) – (ii), (c) – (iii), (d) – (iv)
(2) (a) – (ii), (b) – (iv), (c) – (i), (d) – (iii)
(3) (a) – (ii), (b) – (i), (c) – (iv), (d) – (iii)
(4) (a) – (i), (b) – (ii), (c) – (iv), (d) – (iii)
Answer: Option (3)
Explanation:
Bacteriophage \phi \times 174 is a small virus with a single-stranded DNA genome.
Its genome size is 5386 nucleotides, so (a) correctly matches with (ii).
Bacteriophage lambda is a double-stranded DNA virus.
The length of its DNA is 48502 base pairs, hence (b) matches with (i).
Escherichia coli is a prokaryotic organism.
The size of its genome is approximately 4.6 \times 10^{6} base pairs, so (c) matches with (iv).
The haploid content of human DNA represents the DNA present in one set of chromosomes.
It contains approximately 3.3 \times 10^{9} base pairs, therefore (d) matches with (iii).
Thus, the correct matching is given in option (3).