Sankalp NEET Full Test-5 Question-27 Solution

Question: 27: The ratio of the magnitude of the magnetic field and electric field intensity of a plane electromagnetic wave in free space of permeability \mu_{0} and permittivity \varepsilon_{0} is (Given that \mathrm{c} is velocity of light in free space

(1) c

(2) \frac{1}{\mathrm{c}}

(3) \frac{\mathrm{c}}{\sqrt{\mu_{0} \varepsilon_{0}}}

(4) \frac{\sqrt{\mu_{0} \varepsilon_{0}}}{\mathrm{c}}

Answer: Option (2)

Explanation:

For a plane electromagnetic wave propagating in free space, the electric field E

and magnetic field B are related by

E = cB

where c is the speed of light in free space.

Rearranging the above relation, the ratio of the magnetic field to the electric field is

\frac{B}{E} = \frac{1}{c}

Thus, the ratio of the magnitude of the magnetic field and electric field intensity of a plane electromagnetic wave in free space is \frac{1}{c}.

Hence, the correct option is (2).

Scroll to Top