Sankalp NEET Full Test-5 Question-33 Solution

Question: 33: Let R_{1} be the radius of the second stationary orbit and R_{2} be the radius of the fourth stationary orbit of an electron in Bohr’s model. The ratio \frac{R_{1}}{R_{2}} is :

(1) 0.25

(2) 0.5

(3) 2

(4) 4

Answer: Option (1)

Explanation:

According to Bohr’s model of the hydrogen atom, the radius of the n^{\text{th}} stationary orbit is given by r_{n}=n^{2}a_{0}, where a_{0} is the Bohr radius.

For the second stationary orbit, n=2. Hence, R_{1}=2^{2}a_{0}=4a_{0}.

For the fourth stationary orbit, n=4. Hence, R_{2}=4^{2}a_{0}=16a_{0}.

Now, the required ratio is \frac{R_{1}}{R_{2}}=\frac{4a_{0}}{16a_{0}}=\frac{1}{4}=0.25.

Therefore, the correct option is (1).

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