Question: 56: Match List-I with List-II :
| List – I (Molecules) | List -II (Shape) |
|---|---|
| (a) \mathrm{NH}_{3} | (i) Square pyramidal |
| (b) \mathrm{ClF}_{3} | (ii) Trigonal bipyramida |
| (c) \mathrm{PCl}_{5} | (iii) Trigonal pyramidal |
| (d) \mathrm{BrF}_{5} | (iv) T-shape |
Choose the correct answer from the options given below :
(1) (a) – (ii), (b) – (iii), (c) – (iv), (d) – (i)
(2) (a) – (iii), (b) – (iv), (c) – (ii), (d) – (i)
(3) (a) – (iv), (b) – (iii), (c) – (i), (d) – (ii)
(4) (a) – (iii), (b) – (iv), (c) – (i), (d) – (ii)
Answer: Option (2)
Explanation:
The shape of a molecule is determined using VSEPR theory based on the number of bond pairs and lone pairs around the central atom.
In \mathrm{NH}_{3}, nitrogen has three bond pairs and one lone pair.
This gives a trigonal pyramidal shape. Hence, (a) matches with (iii).
In \mathrm{ClF}_{3}, chlorine has three bond pairs and two lone pairs.
The electron pair geometry is trigonal bipyramidal, and the molecular shape is T-shaped.
Hence, (b) matches with (iv).
In \mathrm{PCl}_{5}, phosphorus has five bond pairs and no lone pairs.
This results in a trigonal bipyramidal shape. Hence, (c) matches with (ii).
In \mathrm{BrF}_{5}, bromine has five bond pairs and one lone pair.
The electron pair geometry is octahedral, and the molecular shape is square pyramidal.
Hence, (d) matches with (i).
Therefore, the correct matching is:
(a) – (iii), (b) – (iv), (c) – (ii), (d) – (i)