Sankalp NEET Full Test-5 Question-63 Solution

Question: 63: 0.01 M acetic acid solution is 1 \% ionised, then pH of this acetic acid solution is :

(1) 3

(2) 2

(3) 4

(4) 1

Answer: Option (3)

Explanation:

Acetic acid is a weak acid and is partially ionised in aqueous solution.

Given concentration of acetic acid is 0.01\,\text{M}

and percentage ionisation is 1\%.

Fraction ionised is:

\frac{1}{100} = 0.01

Hydrogen ion concentration produced is:

[\mathrm{H}^+] = 0.01 \times 0.01 = 1 \times 10^{-4}\,\text{M}

pH of the solution is given by:

\mathrm{pH} = -\log [\mathrm{H}^+]

Substituting the value:

\mathrm{pH} = -\log(1 \times 10^{-4}) = 4

Therefore, the pH of the acetic acid solution is 4.

Hence, option (3) is correct.

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