Question: 65: The half life of a first order reaction is 2000 years. If the concentration after 8000 years is 0.02 M , then the initial concentration was :
(1) 0.16 M
(2) 0.32 M
(3) 0.08 M
(4) 0.04 M
Answer: Option (2)
Explanation:
For a first order reaction, the concentration decreases by half after every half-life.
Given half-life is 2000 years and time elapsed is 8000 years.
Number of half-lives elapsed is:
\frac{8000}{2000} = 4After one half-life, concentration becomes half of the initial concentration.
After four half-lives, the concentration becomes:
\frac{a}{2^4} = \frac{a}{16}Given concentration after 8000 years is:
\frac{a}{16} = 0.02Solving for initial concentration a:
a = 0.02 \times 16 = 0.32Therefore, the initial concentration was 0.32 M.
Hence, option (2) is correct.