Question: 72: The product formed from the following reaction sequence is
Answer: Option (1)
Explanation:
The given starting compound is aniline, C_6H_5NH_2.
In the first step, reaction with acetic anhydride in the presence of pyridine causes acetylation of the amino group.
Aniline is converted into acetanilide, where the NH_2 group becomes NHCOCH_3. This step protects the amino group.
In the second step, treatment with lithium aluminium hydride reduces the amide group. LiAlH_4 converts the CONH group of acetanilide into an amine by
reducing the carbonyl group. As a result, the acetyl group is converted into an ethyl group.
After hydrolysis in the third step, the final product formed is N-ethylaniline,
having the structure C_6H_5NHCH_2CH_3.
This structure corresponds to option (1).
The other options involve hydroxyl substitution on the benzene ring,
which does not occur in this reaction sequence.