Question:96: Match List – I with List – II :
| List – I | List – II |
|---|---|
| (a) In lac operon \mathbf{i} gene codes for | (i) transacetylase |
| (b) In lac operon \mathbf{z} gene codes for | (ii) permease |
| (c) In lac operon y gene codes for | (iii) \beta-galactosidase |
| (d) In lac operon a gene codes for | (iv) Repressor |
Choose the correct answer from the options given below :
(1) (a) – (iii), (b) – (ii), (c) – (i), (d) – (iv)
(2) (a) – (iv), (b) – (iii), (c) – (ii), (d) – (i)
(3) (a) – (iv), (b) – (i), (c) – (iii), (d) – (ii)
(4) (a) – (iii), (b) – (i), (c) – (iv), (d) – (ii)
Answer: Option (2)
Explanation:
The lac operon is a gene regulation system in bacteria that controls lactose metabolism.
The \mathbf{i} gene is a regulatory gene that codes for the repressor protein,
which blocks transcription in the absence of lactose.
The \mathbf{z} gene codes for the enzyme \beta-galactosidase,
which breaks lactose into glucose and galactose.
The y gene codes for permease, a protein that facilitates the entry of lactose into the bacterial cell.
The a gene codes for transacetylase, an enzyme involved in the metabolism of lactose derivatives.
Thus, the correct matching is: (a) repressor, (b) \beta-galactosidase, (c) permease,
and (d) transacetylase.