Sankalp NEET Full Test-6 Question-127 Solution

Question: 127. Match Column – I with Column – II.

Column – IColumn – II
(a) \% \underset{+}{\mathscr{C}} \mathrm{K}_{(5)} \mathrm{C}_{1+2+(2)} \mathrm{A}_{(9)+1} \underline{\mathrm{G}}_{1}(i) Brassicaceae
(b) \oplus \underset{+}{O} \mathrm{~K}_{(5)} \widehat{\mathrm{C}_{(5)}} \widehat{\mathrm{A}_{5}} \underline{\mathrm{G}}_{2}(ii) Liliaceae
(c) \oplus \widehat{\mathrm{P}_{(3+3)} \mathrm{A}} \mathrm{A}_{3+3} \underline{\mathrm{G}}_{(3)}(iii) Fabaceae
(d) \oplus \widehat{\mathrm{K}}_{2+2} \mathrm{C}_{4} \mathrm{~A}_{2-4} \underline{\mathrm{G}}_{(2)}(iv) Solanaceae

Select the correct answer from the options given below.

(a) (iii) (b) (iv) (c) (ii) (d) (i)

(a) (i) (b) (ii) (c) (iii) (d) (iv)

(a) (ii) (b) (iii) (c) (iv) (d) (i)

(a) (iv) (b) (ii) (c) (i) (d) (iii)

Answer: Option (1)

Explanation:

The floral formula in (a) shows zygomorphic flower with diadelphous stamens

\mathrm{A}_{(9)+1}, which is characteristic of Fabaceae.

The floral formula in (b) represents actinomorphic flowers with fused sepals and

petals and bicarpellary ovary, typical of Solanaceae.

The floral formula in (c) shows perianth arranged as \mathrm{P}_{(3+3)}

and six stamens, which is a characteristic feature of Liliaceae.

The floral formula in (d) shows tetradynamous condition with \mathrm{K}_{2+2}

and \mathrm{A}_{2-4}, which is characteristic of Brassicaceae.

Hence, the correct matching corresponds to option (1).

Scroll to Top